-16x^2+128x+12x=0

Solution for -16x^2+128x+12x=0 equation:

-16x^2+128x+12x=0

We add all the numbers together, and all the variables

-16x^2+140x=0

a = -16; b = 140; c = 0;
Δ = b2-4ac
Δ = 1402-4·(-16)·0
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(140)-140}{2*-16}=\frac{-280}{-32}
=8+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(140)+140}{2*-16}=\frac{0}{-32}
=0
$